Is anyone here good with chemistry?

[Zachalmighty]

I have two questions, they are part of a lab with no assosciated reading or lesson. Possibly ahead of what I am learning atm.

I just need to know how to start each problem and from there I can do the math and such myself.

1) You mix a 45.0 mL solution of 0.250 M Al(NO3)3* with a 30.0 mL solution of 0.600 M K2C)3. (a) Give the net ionic equation. (b) How many grams of the precipitate forms? (c) After the reaction, what is the concentration of the excess ions?

*All of the numbers in the listed molecules are subscripts.

2. Give the formula equation, the complete ionic equation, and the net ionic equation of the reaction in water between hydroiodic acid and CH3NH2*.

*the numbers here are subscript as well.

Thanks. I wish there wasn't so much chemistry mixed into my pursuit of a bio degree!

[Ike.]

Typically it's not a good idea to ask forums for help with your homework.

Also I have no idea.

[Kakizaki]

Typically it's not a good idea to ask forums for help with your homework.

Ditto on that.

[Olethros]

Thanks. I wish there wasn't so much chemistry mixed into my pursuit of a bio degree!

If you manage to get through it, you'll never have to deal with it again. So, while I probably could have helped you at one time, this is no longer the case.

Good luck.

[Kakizaki]

^I got out of my lab requirement in college. :)

[Zachalmighty]

Unfortunately, I have to take almost 12 science labs over the course of 4 years.

[James Fiend]

Unfortunately, I have to take almost 12 science labs over the course of 4 years.
I don't envy you. I hate math and science so much.

[StrikeRaider]

I never had to learn any of the ion equations or anything for school. Unless those use the same equations are you use to calculate the transfer of ions between batteries I can't help ya.

[slayn]

Wait until you hit Organic Chemistry. That's when the real fun begins.

[Pixel]

2Al(NO3)3 + 3K2CO3 <=> Al2(CO3)3 + 6KNO3

0.01125 mol (Al)3+
0.03375 mol (NO3)-
0.018 mol (CO3)2-
0.036 mol K+

in 0.075 L

0.005625 mol Al2(CO3)3 with 0.001125 mol (CO3)2- left over
0.03375 mol KNO3 with 0.00225 mol K+ left over

0.005625*233.9903 = 1.316g Al2(CO3)3
0.03375*101.1032 = 3.412g KNO3
0.001125/0.075 = 0.015 mol/L (CO3)2-
0.00225/0.075 = 0.030 mol/L K+

Let me know if I'm close.

[Zachalmighty]

Wait until you hit Organic Chemistry. That's when the real fun begins.
Can't wait to tear my hair out.

2Al(NO3)3 + 3K2CO3 <=> Al2(CO3)3 + 6KNO3

0.01125 mol (Al)3+
0.03375 mol (NO3)-
0.018 mol (CO3)2-
0.036 mol K+

in 0.075 L

0.005625 mol Al2(CO3)3 with 0.001125 mol (CO3)2- left over
0.03375 mol KNO3 with 0.00225 mol K+ left over

0.005625*233.9903 = 1.316g Al2(CO3)3
0.03375*101.1032 = 3.412g KNO3
0.001125/0.075 = 0.015 mol/L (CO3)2-
0.00225/0.075 = 0.030 mol/L K+

Let me know if I'm close.

That looks right! Thanks, now I only really need to do the second part!

[Pixel]

You may want to double check the end product solubilities. If KNO3 is aqueous, you'd have to redo that part.

[StrikeRaider]

No wonder our section of chem had close to a 100% avg. Didn't ever teach/test us about Mols. Still like chem though,

[Zachalmighty]

You may want to double check the end product solubilities. If KNO3 is aqueous, you'd have to redo that part.

Will do, tomorrow before class I am meeting with another to go over the answers.

[slayn]

No wonder our section of chem had close to a 100% avg. Didn't ever teach/test us about Mols. Still like chem though,

Please tell me you're in high school...

[Zachalmighty]

You may want to double check the end product solubilities. If KNO3 is aqueous, you'd have to redo that part.

I double checked and the only thing that was slightly off was that you didn't get rid of the spectator Ions. But i did. So no worries.

[unknown]

Wait until you hit Organic Chemistry. That's when the real fun begins.

Indeed, I hate reaction mechanisms so much.